下述列表计算的结果是a= [1,11,10,10001,10001]a.append(2.5)print(a) A.[1, 11, 10, 10001, 10001, 2.5] B.[2.5,1, 11, 10, 10001, 10001] 下述列表计算的结果是a= [1,11,10,10001,10001]a.append(2.5)print(a) A.[1, 11, 10, 10001, 10001, 2.5] B.[2.5,1, 11, 10, 10001, 10001] 正确答案:A